\(\frac{4x-24}{5x-5}\div\frac{x^2-36}{x^2-2x+1}=\frac{4\left(x-6\right)}{5\left(x-1\right)}\div\frac{\left(x-6\right)\left(x+6\right)}{\left(x-1\right)^2}\)
\(=\frac{4\left(x-6\right)}{5\left(x-1\right)}.\frac{\left(x-1\right)^2}{\left(x-6\right)\left(x+6\right)}=\frac{4\left(x-1\right)}{5\left(x+6\right)}=\frac{4x-4}{5x+30}\)