\(\frac{4}{5.7}+\frac{4}{7.9}+...+\frac{4}{99.101}\)
\(=2.\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{99.101}\right)\)
\(=2.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\right)\)
\(=2.\left(\frac{1}{5}-\frac{1}{101}\right)\)
\(=2.\left(\frac{101}{505}-\frac{5}{505}\right)\)
\(=2.\frac{96}{505}\)
\(=\frac{192}{505}\)
Chúc bạn học tốt !!!