Question

(4/3)^2018÷(16/9)^1008-x=0,6^3÷0,2^3

Answer 1

\(\left(\frac{4}{3}\right)^{2018}:\left(\frac{16}{9}\right)^{1008}-x=0,6^3:0,2^3\)

\(\Leftrightarrow\left[\left(\frac{4}{3}\right)^2\right]^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\left(\frac{16}{9}\right)^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\frac{16}{9}-x=27\)

\(\Leftrightarrow x=\frac{-227}{9}\)

Vậy x = \(\frac{-227}{9}\)