\(x=9120-3311\)
\(x=5809\)
b)68:x-11=6
68:x=6+11
68:x=17
x=4
c)55:x=121
c thì sao ?
a) 43(115-38)+x = 9120
\(43\left(115-38\right)+x=x+3311\)
\(x+3311=2^5.3.5.19\)
\(x+3311=9102\)
x=9102-3311
x=5809
b)68:x-11=6
\(68:x=6+11\)
\(68:x=17\)
\(x=68:17\)
\(x=4\)
c) 55:x=121
\(\frac{5}{11}=\frac{121}{1}\Rightarrow55.1=x.121\)
\(\frac{55.1}{121}=\frac{x.121}{121}\)
\(\frac{55.1}{121}=x\)
\(\frac{5}{11}\)
vậy nếu 55:5.x=121 thì giải sao ạ
55:5.x=121
11.x=121
x=121:11
x=11
để bài câu thứ 3 có j đó sai sai bạn êy
