\(\frac{3A}{4}=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{25.28}.\)
\(\frac{3A}{4}=\frac{4-1}{1.4}+\frac{7-4}{4.7}+\frac{10-7}{7.10}+...+\frac{28-25}{25.28}\)
\(\frac{3A}{4}=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{25}-\frac{1}{28}=1-\frac{1}{28}=\frac{27}{28}\)
\(A=\frac{27.4}{28.3}=\frac{9}{7}\)