bn ơi cho hỏi x ở đâu mak tìm đc vậy?thấy có n thui hà!^^
\(\left(2n-2\right)^2=2^4=\left(-2\right)^4\)
+) \(\left(2n-2\right)^2=2^4\)
\(2n^2-2^2=2^4\)
\(2n^2=2^4:2^2=2^2\)
\(2n=2\)
\(n=2:2=1\)
+) \(\left(2n-2\right)^2=\left(-2\right)^4\)
............... làm tương tự nốt giùm mk ha!chúc học giỏi!^^
\(\left(2n-2\right)^2=16\)
\(\Leftrightarrow\left(2n-2\right)^2=4^2\)
\(\Leftrightarrow2n-2=4\)
\(\Leftrightarrow2n=4+2\)
\(\Leftrightarrow2n=6\)
\(\Leftrightarrow n=\frac{6}{2}\)
\(\Leftrightarrow n=3\)
Vậy n=3
<=>\(\left(2x-2\right)^2=4^2\)
<=>2x-2=4
<=>2x=6
<=>x=3
vậy x=3
\(\left(2n-2\right)^2=16\)
\(\Leftrightarrow\left(2n-2\right)^2=4^2\)
\(\Leftrightarrow2n-2=4\)
\(\Leftrightarrow2n=4+2\)
\(\Leftrightarrow2n=6\)
\(\Leftrightarrow n=3\)
Vậy n = 3
(2n - 2)2 = 16
(2n - 2)2 = 42
\(\Rightarrow\)2n - 2 = 4
\(\Rightarrow\)2n=4+2
\(\Rightarrow\)2n=6
\(\Rightarrow\)n=3
\(\Rightarrow\)n=6:2=
