\(3+\dfrac{x}{5}=\dfrac{-2}{3}\)
\(\dfrac{x}{5}=\dfrac{-2}{3}-3\)
\(\dfrac{x}{5}=\dfrac{-11}{3}\)
\(x.3=5.\left(-11\right)\)
\(x.3=-55\)
\(x=-55:3\)
\(x=\dfrac{-55}{3}\)
vậy \(x=\dfrac{-55}{3}\)
\(3+\dfrac{x}{5}=\dfrac{-2}{3}\)
\(\dfrac{x}{5}=\dfrac{-2}{3}-3\)
\(\dfrac{x}{5}=\dfrac{-11}{3}\)
\(x.3=5.\left(-11\right)\)
\(x.3=-55\)
\(x=-55:3\)
\(x=\dfrac{-55}{3}\)
vậy \(x=\dfrac{-55}{3}\)
a,5^x+4-3×5^x+3=2×5^11
b,3×5^x+2+4×5^x-3=19×5^10
c,6×8^x-1+8^x-1=6×8^19+8^21
d,5×2^x+3×2^x+2=5×2^5+3×2^7
3(x-1/2)-5(x-3/5)=-x+1/5
-5(x+1/5)-1/2(x-2/3=3/2x-5/6
Cho đa thức B(x) = 2\(x^{^{ }2}\)-4x + 3. Tính B(3), B(-\(\dfrac{1}{2}\) )
Cho đa thức M(x) = 7\(x^3\)- 3\(x^4\)- \(x^2\) + 3\(x^2\)- \(x^3\)- 3\(x^4\)- 6\(x^3\)
Cho đa thức N(x) = 3x - 5\(x^3\) + 8\(x^2\)- 5x + 5\(x^3\) + 5
Bài 1: a, x + 0,5 = -2/3 b, x - (-2/5) = 5/7 c, 5/4 - 6x = 7 1/2 d, 3 - 2x - (5/4 - 7/5) = 9/20 bài 2: a, x : (-2/3) mũ 3 = -2/3 b, (2/5) mũ 5 nhân x = (2/5) mũ 7 c, 343/125 = (7/5) mũ x d, (-1/3) nhân x = 1/243
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
Tìm số hữu tỉ x biết
a) 2/3.x-2/5=1/2.x-1/3
b) 1/3.x+2/5(x+1)=0
c) 2/3-1/3(x-3/2)-1/2(2x+1)=5
d) 11/5-(7/9-x).3/8=61/90+x/3
Tìm x nguyên sao cho:
a) 5*3^x+6 = 2*3^5 + 3*3^5
b) 5^x+4-3*5^x+3=2*5^4
tính hợp lí
a,\(\dfrac{27}{2}\) x 7,5 + \(\dfrac{27}{2}\) x 2,5 -150
b,3\(^3\)x \(\dfrac{18}{5}\) - 3\(^3\) x 2\(\dfrac{2}{5}\) - 3\(^3\) x \(\dfrac{6}{5}\)
TÌM X:
a) 5x-3=2x+1
b) 3.( x-5) - 5.(x+1)= 15
c) x-5/3 - x+2/5 = 1/2
d) 3x-7/2 = 5x-2/3
e) -2.(x-3) + 5.(x-1)= 3+x
f) x.(x-5)- x.(x-2)= 6-x
g) 1/3x-2=1/4x+4