\(3x^2-5x-8\)
\(=3x^2+3x-8x-8\)
\(=\left(3x^2+3x\right)-\left(8x+8\right)\)
\(=3x\left(x+1\right)-8\left(x+1\right)\)
\(=\left(3x-8\right)\left(x+1\right)\)
3x2 - 5x - 8 = 3x2 + 3x - 8x - 8 = ( 3x2 + 3x ) - ( 8x + 8 )
= 3x( x + 1 ) - 8( x + 1 ) = ( 3x - 8 )( x + 1 )
3x2-5x-8
=3x2+3x-8x-8
=3x(x+1)-8(x+1)
=(x+1)((3x-8)