Ta có:3x+2 - 5 . 3x = 36
\(\Rightarrow\)3x.9-5.3x=36
\(\Rightarrow\)3x(9-5)=36
\(\Rightarrow\)3x.4=36
\(\Rightarrow\)3x=9
\(\Rightarrow\)3x=32
\(\Rightarrow\)x=2
Vậy x=2
\(3^{x+2}-5.3^x=36\)
\(\Rightarrow3^x\left(3^2-5\right)=36\)
\(\Rightarrow3^x.\left(9-5\right)=36\)
\(\Rightarrow3^x.4=36\)
\(\Rightarrow3^x=9\)
\(\Rightarrow x=2\)
\(3^{x+2}-5\cdot3^x=36\)
\(\Rightarrow3^x\cdot3^2-5\cdot3^x=36\)
\(\Rightarrow3^x\left(9-5\right)=36\)
\(\Rightarrow3^x\cdot4=36\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy
