ok
3x+2 - 3x = 216
3x.32 - 3x.1 = 216
3x.(32-1) = 216
3x.(9-1) = 216
3x.8 = 216
3x = 216 : 8
3x = 27
3x = 33
x = 3
Vậy x = 3
ok
3x+2 - 3x = 216
3x.32 - 3x.1 = 216
3x.(32-1) = 216
3x.(9-1) = 216
3x.8 = 216
3x = 216 : 8
3x = 27
3x = 33
x = 3
Vậy x = 3
Tim x:
a/ \(3^{x+2}-216=3^x\)
b/\(3^{x-2}+216=3^x\)
c/\(2^{x+1}-48=2^{x-1}\)
d/\(2^{x+3}-56=2^x\)
tim x,y,z biet :
x^3/8=y^3/64=z^3/216 va x^2+y^2+z^2=14
tim n
cau a ; (9/25)^n=(3/5)^4
cau b ; (2^n-2)^2=16
cau c (1-x)^3=216
3^x^2-3^x=162
tim x y z x/2=y/3 y/4=z/5 va x^2-y^2=16
3x/8=3y/6y=3z/216 va 2x^2+2y^2-z^2=1
Tim x,y biet:
a)\(\frac{x}{y}=\frac{5}{3}\)va x+y=16 b)3x+2-3x=216 voi \(x\in N\)
3^(x+2)-3^x=216=> x=3 các banjgiups mình lời giải nha
2^(x+1)×3^x-6^x=216
3^x+2^x=216
Tìm x biết:
|x|0,139=3
2|5x-3|-2x=14
3 mũ x - 3 mũ x+2 =-216