\(3x-9x^2-4-\dfrac{2}{3}x+2=\dfrac{1}{2}x-3\)
<=>\(9x^2-\dfrac{11}{6}x-1=0\)
<=>\(\left(9x^2-\dfrac{11}{6}x+\dfrac{121}{1296}\right)=\dfrac{1417}{1296}\)
<=>\(\left(3x+\dfrac{11}{36}\right)^2=\left(\sqrt{\dfrac{1417}{1296}}\right)^2\)
<=>\(\left[{}\begin{matrix}3x+\dfrac{11}{36}=\sqrt{\dfrac{1417}{1296}}\\3x+\dfrac{11}{36}=-\sqrt{\dfrac{1417}{1296}}\end{matrix}\right.\)