3 ( x - 2 ) + ( x - 1 ) = 10
3x - 6 + x - 1 = 10
4x -7 = 10
4x = 10 + 7
4x = 17
x = 17 : 4
x = \(\frac{17}{4}\)
\(3\left(x-2\right)+\left(x-1\right)=10\)
=> \(3x-6+x-1=10\)
=> \(\left(3x+x\right)+\left(-6-1\right)=10\)
=> \(4x-7=10\Rightarrow4x=10+7=17\)
=> \(x=\frac{17}{4}\)