Question

3x-27x³=0

Answer 1

=>3x(1-9x²)=0

=>3x(1-3x)(1+3x)=0

hay \(x\in\left\{0;\dfrac{1}{3};-\dfrac{1}{3}\right\}\)

Answer 2

`-3(9x^2 - 1) = 0`

`-3(3x-1)(3x+1) = 0`

`->` \(\left[{}\begin{matrix}3x-1=0\\3x+1=0\end{matrix}\right.\)

`->` \(\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{1}{3}\end{matrix}\right.\)