ta có : \(\left(3x-1\right)^3=\left(-\frac{2}{3}\right)^3\)
=> \(3x-1=-\frac{2}{3}\)
=> \(3x=\frac{1}{3}\)
=> \(x=\frac{1}{9}\)
Vậy \(x=\frac{1}{9}\)
(3x-1)^3=-8/27
3x+1= 27
(2x-1)3=8
Tìm x, biết: (3x-1)3 = (-8)/27
(3x-1)^3=-8/27
Tìm x:
(3x-1)^3=8/27
a/ (3x+ 1/2)3 = -27/8
b/ 12-3x2 = -3
A)(2X+3)^2=9/121
B)(3X-1)^3=-8/27
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
tìm x
(3x-1)^3=-8/27
x^3/3=9
x^10=25.x^8
giúp mình nhé
