Question

3\(\sqrt{x}+1=40\)

tìm x

 

Answer 1

\(3\sqrt{x}+1=40\)

\(\Leftrightarrow\)\(3\sqrt{x}=40-1\)

\(\Leftrightarrow\)\(3\sqrt{x}=39\)

\(\Leftrightarrow\sqrt{x}=\frac{39}{3}\)

\(\Leftrightarrow\sqrt{x}=13\)

\(\Leftrightarrow\)\(x=169\)

​\(x=-169\)

Answer 2

\(3\sqrt{x}+1=40\)

\(\Leftrightarrow3\sqrt{x}=39\)

\(\Leftrightarrow\sqrt{x}=13\)

\(\Leftrightarrow x=13^2\)

\(\Leftrightarrow x=169\)