Question

 

_{\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)}

Answer 1

\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)

      \(\frac{10}{3}x+\frac{67}{4}=\frac{-53}{4}\)

      \(\frac{10}{3}x\)             =\(\frac{-53}{4}-\frac{67}{4}\)

       \(\frac{10}{3}x\)            =-30

             \(x\)            =-30:\(\frac{10}{3}\)

             \(x\)            =-9

Answer 2

\(3\frac{1}{3}x=-13,25-\frac{67}{4}\)

\(3\frac{1}{3}x=-13,25-16,75\)

\(3\frac{1}{3}x=-3,5\)

\(x=-3,5:\frac{10}{3}\)

\(x=-3,5.\frac{3}{10}\)

\(x=1,05\) hoặc \(x=\frac{105}{100}\)