Question

\(3^8:3^4+2^2:2^3\)

\(3.4^2-2.3^2\)

\(\left(4^6.3^4.9^3\right):6^{12}\)

Answer 1

3⁸:3⁴+2²:2³=81,5

3.4²-2.3²=30

(4⁶.3⁴.9³):6¹²=1/9

Answer 2

3⁸:3⁴+2²:2³=3^8-4+2^2-3=3⁴+2^-1=81+0,5=81,5

3.4²-2.3²=3.4²-2.3.3=3.4²-6.3=3.(4²-6)=3.10=30

(4⁶.3⁴.9³):6¹²=(4⁶.3⁴.3⁶):6¹²=(4⁶.3⁴⁺⁶):6¹²=(2¹².3¹⁰):6¹²=\(\frac{2^{12}.3^{10}}{6^{12}}\)=\(\frac{1}{9}\)

Answer 3

=3^8-6+2^2-3=3^2+2^-1=9+0.5=9.5

=3*16-2*9=48-18=30

=(4^6*3^4*9^3)/(3^2*4^6*9^3*3^4)=1/9=\(\frac{1}{9}\)