Question

(36.2-72).(1+3+5+...+97+99)

Answer 1

(36.2-72).(1+3+5+...+97+99)

= 0 x ( 1 + 3 + 5 + ...+ 97 + 99 )

= 0

Vì số nào nhân với 0 vẫn bằng 0

Answer 2

( 36 . 2 - 72 ) . ( 1 + 3 + 5 + ... + 97 + 99 )

= ( 72 - 72 ) . ( 1 + 3 + 5 + ... + 97 + 99

= 0 . ( 1 + 3 + 5 + ... + 97 + 99 )

= 0

Answer 3

(36.2-72).(1+3+5+...+97+99)

= (72-72).(1+3+5+...+97+99)

= 0.(1+3+5+...+97+99)

= 0

Answer 4

(36.2-72).(1+3+5....+97+99) 

= (72-72).(1+3+5...+97+99)

=0.(1+3+5...+97+99)

=0

## Học Tốt ##