\(30\cdot\left(x-2\right)-28\left(x-5\right)-24=30\)
<=> \(30\cdot x+30\cdot2-\left(2\cdot x-2\cdot5\right)-24=30\)
<=> \(30x+60-2x+10-24=30\)
<=> \(28x=30+24-10-60\)
<=> \(28x=-16\)
<=> \(x=-\frac{16}{28}\)
<=> \(x=-\frac{4}{7}\)
30.(x+2)-2.(x-5)-24=30
30x+60-2x+10-24=30
28x+46=30
28x+46-30=0
28x-16=0
28x=16
x=4/7
Vậy x=4/7