Ta có:
30+32+...+32002
=1+32+33+...+32002
Coi A=1+32+33+...+32002
=>3A=3+32+...+32003
=> 2A=3A-A=(3+33+...+32003)-(1+32+...+32002)
=3+32002-1-32
=32002+3-1-9
=32002-7
=> A=\(\frac{3^{2002}-7}{2}\)
Ta có:
30+32+...+32002
=1+32+33+...+32002
Coi A=1+32+33+...+32002
=>3A=3+32+...+32003
=> 2A=3A-A=(3+33+...+32003)-(1+32+...+32002)
=3+32002-1-32
=32002+3-1-9
=32002-7
=> A=\(\frac{3^{2002}-7}{2}\)
Cho S=30+32+34+...+32002
a) Tính S
b) Chứng minh S chia hết cho 7
Tính nhanh:30+32+32+...+39+40
Tính nhanh 30+32+32+.....+39+40
A=26+27+28+29+30+32+32+33
so sanh 32^30 và 8^30
Tính hợp lý:
45-58+(-45)+(+58)-3
(-57)-(-12)+3-(-57)
-(-24)-(-30)+(-24)-30+8
-(-12)+(+19)-(+12)+8-19
47-(-53)+(-47)-(+53)
-(+28)+32-(-28)+(-34)
15-(+72)+(-15)+(+72)
20-(+46)+(-25)-(-46)
28-(-32)+(-28)-32+5
-75+(-49)+(+75)+49-12
Giúp e vs ạ
(7/16 + -1/8 + 9/32) ;5/4
-25/30 x 37/44 + -25/30 x 13/44+-25/30 x -6/44
30 + ( 32 - x ) = 10
30+31+32+...+40
30+31+32+...+40