Question

(3-x)*(y+2)=5

 

Answer 1

(3 - x) * (y + 2) = 5

\(\orbr{\begin{cases}3-x=5\\y+2=5\end{cases}}\)

\(\orbr{\begin{cases}x=3-5\\y=5-2\end{cases}}\)

\(\orbr{\begin{cases}x=-2\\y=3\end{cases}}\)

Vậy x = -2 và y = 3

Answer 2

=> ( 3 -x ); ( y + 2 ) \(\in\)Ư(5) \(\in\){ -5; -1 ; 1; 5 }

Th1 : \(\hept{\begin{cases}3-x=-1=>x=3--1=4\\y+2=-5=>y=-5-2=-7\end{cases}}\)

Th2 \(\hept{\begin{cases}3-x=-5=>x=-5+3=-2\\y+2=-1=>y=-1+2=1\end{cases}}\)

Th3 \(\hept{\begin{cases}3-x=1=>x=3-1=2\\y+2=5=>y=5-2=3\end{cases}}\)

Th4 \(\hept{\begin{cases}3-x=5=>x=3-5=-2\\y+2=1=>y=1-2=-1\end{cases}}\)