\(\frac{\left(3-x\right)^{10x}}{\left(3-x\right)^{20}}=1\Leftrightarrow\left(3-x\right)^{10x-20}=\left(3-x\right)^{10\left(x-2\right)}=1\\ \)
\(\orbr{\begin{cases}x-2=0=>x=2\\3-x=+-1\orbr{\begin{cases}x=2\\x=4\end{cases}}\end{cases}}\)\(\orbr{\begin{cases}x-2=0\Rightarrow x=2\\3-x=!1!\end{cases}}\)\(\orbr{\begin{cases}x=2\\x=4\end{cases}}\)