\(\left[3.\left(x+2\right):7\right].4=120\)
\(\Leftrightarrow\left[3.\left(x+2\right):7\right]=30\)
\(\Leftrightarrow3.\left(x+2\right)=210\)
\(\Leftrightarrow\left(x+2\right)=70\)
\(\Leftrightarrow x=68\)
Vậy \(x=68\)
[3.(x+2):7]=120:4=30
3.(x+2)=30x7=210
x+2=210:3=7
x=7-2
x=5
vậy x =5