Question

3. PTDTTNT

a) x^16 - 1

b) x^36 - 64

C) x^6 + y^6

d) a. ( x+5 ) . ( x+6 ) . ( x+10 ) . ( x+1 ) - 3x^2

Answer 1

Phân tích đa thức thành nhân tử:

a \(x^{16}-1\)

\(=\left(x^8\right)^2-1^2\)

\(=\left(x^8-1\right)\left(x^8+1\right)\)

b, \(x^{36}-64\)

\(=\left(x^{18}\right)^2-8^2\)

\(=\left(x^{18}-8\right)\left(x^{18}+8\right)\)

\(=\left[\left(x^6\right)^3-2^3\right]\left[\left(x^6\right)^3+2^3\right]\)

\(=\left(x-2\right)\left(x^{12}+2x+4\right)\left(x+2\right)\left(x^{12}-2x+4\right)\)

c, \(x^6+y^6\)

\(=\left(x^2\right)^3+\left(y^2\right)^3\)

\(=\left(x^2+y^2\right)\left(x^4-x^2y^2+y^4\right)\)