\(=3-1+\frac{1}{2^2.2}\)
\(=2+\frac{1}{8}=\frac{17}{8}\)
\(3-\left(\frac{-6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
\(=3-1+\frac{1}{4}:2\)
\(=3-1+\frac{1}{8}\)
\(=4+\frac{1}{8}\)
\(=\frac{32}{8}+\frac{1}{8}\)
\(=\frac{33}{8}\)
3 - 1 + \(\frac{1}{4}\): 2 = 2 + \(\frac{1}{8}\)= \(\frac{16}{8}+\frac{1}{8}=\frac{17}{8}\)
