\(3\frac{1}{4}x-\frac{7}{6}x=\frac{-5}{12}+\frac{12}{3}\)
= \(\frac{13}{4}x-\frac{7}{6}x=\frac{-5}{12}+\frac{12}{3}\)
= \(x.\left(\frac{13}{4}-\frac{7}{6}\right)=\frac{43}{12}\)
= \(x.\frac{25}{12}=\frac{45}{12}\)
\(x=\frac{45}{12}:\frac{25}{12}\)
\(x=\frac{9}{5}\)
\(3\frac{1}{4}x-\frac{7}{6}x=-\frac{5}{12}+\frac{12}{3}\)
\(\frac{13}{4}x-\frac{7}{6}x=-\frac{5}{12}+\frac{48}{12}\)
\(\left(\frac{13}{4}-\frac{7}{6}\right)x=\frac{43}{12}\)
\(\frac{25}{12}x=\frac{43}{12}\)
\(x=\frac{43}{25}\)
\(3\frac{1}{4}x-\frac{7}{6}x=\frac{-5}{12}+\frac{12}{3}\)
\(\Rightarrow\frac{13}{4}x-\frac{7}{6}x=\frac{43}{12}\)
\(\Rightarrow\frac{25}{12}x=\frac{43}{12}\)
\(\Rightarrow x=\frac{43}{12}\div\frac{25}{12}\)
\(\Rightarrow x=\frac{43}{25}\)
Vậy \(x=\frac{43}{25}\)