\(2x=\frac{y}{3}\Rightarrow\frac{x}{\frac{1}{2}}=\frac{y}{3}\Rightarrow\frac{x}{\frac{1}{2}}=\frac{3y}{9}\)
Theo t/c dãy tỉ số = nhau ta có:
\(\frac{x}{\frac{1}{2}}=\frac{3y}{9}=\frac{x-3y}{\frac{1}{2}-9}=\frac{34}{-\frac{17}{2}}=34.\left(-\frac{2}{17}\right)=-4\)
=> \(\frac{x}{\frac{1}{2}}=-4\Rightarrow x=-4.\frac{1}{2}=-2\)
=>\(\frac{y}{3}=-4\Rightarrow y=-4.3=-12\)
Vậy x=-2; y=-12.