\(\left(2\cdot x-3\right)\cdot3-5=10\)
\(\left(2x-3\right)\cdot3=15\)
\(2x-3=5\)
\(2x=8\)
\(x=4\)
\(\left(2\times x-3\right):3-5=10\)
\(\left(2\times x-3\right)\times3=10+5\)
\(\left(2\times x-3\right)\times3=15\)
\(2\times x-3=15:3\)
\(2\times x-3=5\)
\(2\times x=5-3\)
\(2\times x=2\)
\(x=2:2\)
\(x=1\)
(2xx-3)x3-5=10
(2xx-3)x3=10+5=15
(2xx-3)=15:3=5
2xx=5+3=8
2xx=8
xx=8:2=4
x=2
Vậy x=2
\(\left(2×x-3\right)×3-5=10\)
\(\left(2×x-3\right)×3=10+5=15\)
\(2×x-3=15:3=5\)
\(2×x=5+3=8\)
\(x=8:2=4\)
( 2 x x - 3 ) x 3 - 5 = 10
2 x x = { 10 + 5 } : 3 + 3
2 x x = 8
=> x = 8 : 2
=> x = 4
\(\left(2.x-2\right).3-5=10\)
\(\left(2x-3\right).3=15\)
\(2x-3=5\)
\(2x=8\)
\(x=4\)