\(2x+\left(5-x\right)+3\left(x-79\right)=0\)
\(\Leftrightarrow2x+5-x+3x-237=0\)
\(\Leftrightarrow4x-232=0\)
\(\Leftrightarrow4x=232\)
\(\Leftrightarrow x=58\)
Tính giá trị biểu thức: \(P=\frac{7\cdot X-1}{X+12}\), biết:
\(\left(3+X\right)+\left(5+2X\right)+\left(9+4X\right)+...+\left(129+64X\right)+\left(257+128X\right)=1283\)
Please help me! I will tick you more.
\(\left(x-3\right)\cdot\left(y-2\right)=7\)
\(\left(x-1\right)\cdot\left(x-1\right)=2\)
\(\left(x-1\right)\cdot\left(y-2\right)=2\)
GIẢI GIÚP EM VỚI
Bài 1:
\(a,\left(x-\frac{1}{2}\right)\cdot\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+......+\frac{1}{90}\right)=\frac{1}{3}\)
\(b,\frac{1}{1\cdot6}+\frac{1}{6\cdot11}+.....+\frac{1}{96\cdot101}=\frac{1}{10\cdot x}\)
\(c,460+85\cdot4=\frac{x+175}{5}+30\)
\(d,\left(x-5\right)\cdot\left(10-9\frac{40}{41}\right):\left(1-\frac{81}{82}\right):\left(1-\frac{204}{205}\right)=2050\)
Tìm x biết:\(1-\left(3\frac{3}{8}+x-2\frac{5}{24}\right)\cdot\frac{12}{17}=0\)
Tìm \(x\)sao cho:
\(\left(x+\frac{1}{1\cdot3}\right)+\left(x+\frac{1}{3\cdot5}\right)+\left(x+\frac{1}{5\cdot7}\right)+...+\left(x+\frac{1}{23\cdot25}\right)=11\cdot x+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\right)\)
1,Tính nhanh
a,3x\(\left(\frac{1}{7}+\frac{1}{3}-\frac{3}{14}\right):\frac{11}{14}\)
b,\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)
3,Tìm x,biết
a,\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+......+\frac{2}{x\cdot\left(x+1\right)}=\frac{2016}{2018}\)
b,720:\(720:[41-\left(2\cdot x-5\right)]=120\)
\(\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)\cdot....\cdot\left(1-\frac{1}{256}\right)\cdot x=\frac{108}{7}\)
TÌM X HỘ MIK NHA MÌNH CẢM ƠN\(\left(X+\frac{1}{1\cdot3}\right)+\left(X+\frac{1}{3\cdot5}\right)+...+\left(X+\frac{1}{23\cdot25}\right)=11\cdot X+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{242}\right)\)
\(\left(1+\frac{1}{2}\right)\cdot\left(1+\frac{1}{3}\right)\cdot\left(1+\frac{1}{4}\right)\cdot....\cdot\left(1+\frac{1}{98}\right)\cdot\left(1+\frac{1}{99}\right)=\)?
