Question

(2x+5)(4x+3)-8x(x-3)=10

Answer 1

\(\left(2x+5\right)\left(4x+3\right)-8x\left(x-3\right)=10\\ \Rightarrow8x^2+20x+6x+15-8x^2+24x=10\\ \Rightarrow50x=-5\\ \Rightarrow x=-\dfrac{1}{10}\)

Answer 2

(2x+5)(4x+3)-8x(x-3)=10

<=>8x²+26x+15-(8x²-24x)=0

<=>8x²+26x+15-8x²+24x=0

<=>50x+15=0

<=>50x=-15

<=>x=-\(\dfrac{3}{10}\)