2x=3y=5z
nên x/15=y/10=z/6
Đặt x/15=y/10=z/6=k
=>x=15k; y=10k; z=6k
\(\left|x+y-z\right|=95\)
\(\Leftrightarrow\left|15k+10k-6k\right|=95\)
\(\Leftrightarrow\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\)
TH1: k=5
=>x=75; y=50; z=30
TH2: k=-5
=>x=-75; y=-50; z=-30