Question

(2x+3/5)2-9/25=0

giup mk cai nha

Answer 1

Sửa đề: 

\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)

\(\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)

\(\left(2x+\frac{3}{5}\right)^2=\left(\pm\frac{3}{5}\right)^2\)

\(\Rightarrow\orbr{\begin{cases}2x+\frac{3}{5}=\frac{3}{5}\\2x+\frac{3}{5}=-\frac{3}{5}\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=0\\2x=-\frac{6}{5}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=-\frac{3}{5}\end{cases}}}\)

Vậy \(x=0\) hoặc \(x=-\frac{3}{5}\)

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