(2x+3/5)2-9/25=0
(2x+3/5)2 =0+9/25
(2x+3/5)2 =9/25
(2x+3/5)2 = (3/5)2
2x+3/5 =3/5
2x =3/5-3/5
2x =0
x =0:2
x =0
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tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
tìm x:
(2x+3/5)mũ 2-9/25=0
(2x +3/5) mũ 2-9/25=0
a) (2x+3/5)2-9/25=0
b)3(3x-1/2)3+1/9=0
(2x+3/5)^2-9/25=0
3(3x-1)^3+1/9=0
nêu cách làm
Tìm x biết:
a) (2x + 3/5)^2 - 9/25 = 0
b) 3.(3x - 1/2)^3 +1/9 =0
TIM X BIET
(2X-3/5)^2-9/25=0
- Tìm x
2 . ( x - 1/2 ) ^ 3 - 1/4 = 0
( 3x -1 ) ( - 1/2x + 5 ) = 0
( 2n + 3/5 ) ^ 2 - 9/25 = 0
3 ( 3n - 1/2 ) ^ 3 + 1/9 = 0
(2x+3/5)^3-9/25=0