ta có
2x+2\(⋮\)3x-1
\(\Rightarrow\)3(2x+2)\(⋮\)3x-1
\(\Rightarrow\)6x+6\(⋮\)3x-1
6x-2+8\(⋮\)3x-1
\(\Rightarrow\)8\(⋮\)3x-1
\(\Rightarrow\)3x-1\(\in\)Ư(8)
\(\Rightarrow\)3X-1\(\in\){\(\pm\)1,\(\pm\)2\(\pm\)4,\(\pm\)8}
\(\Rightarrow\)x\(\in\){0,1,-1,3}