\(2x^2-1=49\)
\(2x^2=49+1\)
\(2x^2=50\)
\(x^2=50:2\)
\(x^2=25\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
\(2x^2-1=49\)
\(\Leftrightarrow2x^2=50\)
\(\Leftrightarrow x^2=50:2\)
\(\Leftrightarrow x^2=25\)
\(\Leftrightarrow x=\sqrt{25}\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
2x2 - 1 = 49
<=>2x2 = 49 + 1
<=> 2x2 = 50
<=> x2 = 50 : 2
<=> x2 = 25
<=> x2 = 52
=> x = 5
\(2x^2-1=49\)
\(2x^2=49+1\)
\(2x^2=50\)
\(x^2=50\div2\)
\(x^2=25\)
\(\Rightarrow x\in\){5 ; -5}