e) ( x + 3)^3 = ( 2x) ^3
f) ( 5 - x )^5 = 32
g) ( 5x - 6)^3 = 64
h)5 . 9^x = 405
i) 11^5 : 11^ n - 2 = 11^5
k) ( 3x)^3 = ( 2x + 1)^3
|-2x + 1|=3
(x+9-17)-24=11-(x+17)
-3.(2x+1)-11=-8-2.(x+3)
|x+4|+x=12-x
-17.(-3)-(x+29)=-11-3x
15-2x=-11-3x
-17-4x=-19.3-2x
46-(52-x)=12.(-7)+2x
[ ( 2x - 11 ) : 3 + 11 ] x 5 = 20
a) -2x - (-17)= 9 b) 11 + (15 – x) = 1
c) 53 – 7x = 57 : 55 |
b) 11 + (15 – x) = 1
d) 29 +9.x2 = 110
e) (2x-4).(3-x) = 0
g) 2x + 1 chia hết cho x -2
giải bài toán tìm x sau:(2x-11)^5 = (2x-11)^3 với
Bài 1Tìm x
A; 3 1/3 (3 1/4+2x)=6 2/3
B; x-25%x=6/11 (1/2+3/4-1/3)
C; (4,5-2x)×1 4/7=11/14
D; (-3)^2-|2x+3|=4
Tìm x thuộc Z sao cho: a) 3x + 5 chia hết cho x; b) 4x + 11 chia hết cho 2x + 3; c) x 2 + 2x -11 chia hết cho x + 2
Tìm x Î Z sao cho:
a) 3x + 5 chia hết cho x;
b) 4x + 11 chia hết cho 2x + 3;
c) x 2 + 2 x - 11 chia hết cho x + 2
a, 2.x + 7 = 15
b, 25 – 3.(6 – x) = 22
c, [(2x – 11) : 3 + 1].5 = 20
d, (25 – 2x)3 : 5 – 32 = 42
e, 2 . 3x = 10 . 312 + 8 . 274
g, x – 12 = (–8) + (–17)
h, 7 – 2x = 18 – 3x
i, 3(x + 5) – x – 11 = 24