\(\Leftrightarrow\left(2x+1\right)^2=5^2\)
\(\Leftrightarrow2x+1=5\)
\(\Leftrightarrow2x=5-1\)
\(\Leftrightarrow2x=4\)
\(\Leftrightarrow x=4:2=2\)
Ta có:25=5.5=5^2
\(^{^{ }\left(2x+1\right)^2=25=5^2}\)
=> 2x+1=5
2x=5-1
2x=4
x=4:2
x=2
(2x+1)2=25
(2x+1)2=52
suy ra 2x+1=5
2x =5-1
2x =4
x =4:2
x =2