Ta có :
(2x-4)(x+3)=0
TH1:
2x-4=0
2x=0+4
2x=4
x=4:2
x=2
TH2:
x+3=0
x=0-3
x=-3
(2x - 4)(x + 3) = 0
TH1: 2x - 4 = 0
2x= 4
x = 2
TH2: x + 3 = 0
x = 0 - 3
x = -3
Vậy x \(\in\) {-3 ; 0 }
(2x - 4)(x + 3) = 0
Th1: 2x- 4 = 0
2x = 4
x = 2
TH2: x + 3 = 0
x= 0 - 3
x = -3
\(x\in\left\{-3;2\right\}\)