Question

-2(x-3)/5=y+4/-4=3(z-5)/2 và x-y+z=-1

ai nhanh nhất mình tick

Answer 1

ta có:

\(\frac{-2\left(x-3\right)}{5}\)=\(\frac{y+4}{-4}\)=\(\frac{3\left(z-5\right)}{2}\)

đặt\(\frac{-2\left(x-3\right)}{5}\)=\(\frac{y+4}{-4}\)=\(\frac{3\left(z-5\right)}{2}\)=k

\(\Rightarrow\)\(x=\frac{-5k+6}{2}\)

         y=\(-4\left(k+1\right)\)

          \(z=\frac{2k+5}{2}\)

mà x-y+z=-1

\(\Rightarrow\)\(\frac{-5k+6}{2}\)+\(\frac{8\left(k+1\right)}{2}\)+\(\frac{2k+5}{2}\)= -1

\(\Rightarrow\)\(-2=15k+19\)

\(\Rightarrow\)\(-21=15k\)

\(\Rightarrow\)\(k=\frac{-21}{15}\)

\(\Rightarrow\)Tự tìm nốt x,y,z