\(\left(2x-3\right)^2=36\)
\(\Leftrightarrow\left(2x-3\right)^2=6^2\)
\(\Rightarrow2x-3=6\)
\(\Rightarrow2x=9\)
\(\Rightarrow x=4,5\)
(2x - 3)2 = 36
=> 2x - 3 = 6 hoặc 2x - 3 = - 6
=> 2x = 9 hoặc 2x = - 3
=> x = 4,5 hoặc x = - 1,5
\(\left(2x-3\right)^2=36\)
\(\left(2x-3\right)^2=6^2\)hoặc\(\left(-6^2\right)\)
\(\Rightarrow2x-3=-6\)hoặc \(2x-3=6\)
Th1: \(2x-3=-6\)
\(2x=3\)
\(x=1,5\)
Th2:\(2x-3=6\)
\(2x=9\)
\(x=4,5\)
Vậy \(x=1,5\) hoặc \(x=4,5\)