(2x-1)6=(2x-1)8
=>2x-1=0=>2x=1=>x=1/2
2x-1=1=>2x=2=>x=1
Vậy x=1/2
x-1
<=> (2x-1)^8 - (2x-1)^6 = 0 <=> (2x-1)^6 ( (2x-1)^2 -1) = 0 <=>\(\orbr{\begin{cases}\left(2x-1\right)^6\\\left(\left(2x-1^2\right)-1\right)=0\end{cases}\Leftrightarrow\orbr{\begin{cases}2x-1=0\\\left(2x-1\right)^2=1\Leftrightarrow\end{cases}}\orbr{\begin{cases}x=\frac{1}{2}\\\orbr{\begin{cases}2x=2\\2x=0\end{cases}}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\\orbr{\begin{cases}x=1\\x=0\end{cases}}\end{cases}}}\)
Vậy x thuộc {1/2; 1; 0}