Question

2^x-1+4*2^x=18

Answer 1

\(\Leftrightarrow\frac{1}{2}2^x+4\cdot2^x=18\)

\(\Leftrightarrow\left(\frac{1}{2}+4\right)2^x=18\)

\(\Leftrightarrow9\cdot2^x=36\Leftrightarrow2^x=4\Leftrightarrow x=2\).

Answer 2

2^x-1+4.2^x=18

2^x-1+4.2^x=18

2^x:2+4.2^x=18

2^x.1/2+4.2^x=18

2^x(1/2+4)=18

2^x.4,5=18

2^x=18:4,5

2^x=4

2^x=2²

Vậy :x=2

Answer 3

2^x-1+4.2^x=18

2^x-1+4.2^x=18

2^x:2+4.2^x=18

2^x.1/2+4.2^x=18

2^x(1/2+4)=18

2^x.4,5=18

2^x=18:4,5

2^x=4

2^x=2²

Vậy :x=2