\((2x-1)^{2}-9=16\)
\(\Leftrightarrow\)\((2x-1)^{2}=25\)
\(\Leftrightarrow\)\(\left[\begin{array}{} 2x-1=5\\ 2x-1=-5 \end{array} \right.\)
\(\Leftrightarrow\)\(\left[\begin{array}{} x=3\\ x=-2 \end{array} \right.\)
(2x - 1)2 - 9 = 16
\(\Leftrightarrow\) (2x - 1)2 - 9 - 16 = 0
\(\Leftrightarrow\) (2x - 1)2 - 25 = 0
\(\Leftrightarrow\) (2x - 1)2 - 52 = 0
\(\Leftrightarrow\) (2x - 1 - 5)(2x - 1 + 5) = 0
\(\Leftrightarrow\) (2x - 6)(2x + 4) = 0
\(\Leftrightarrow\) Khi 2x - 6 = 0 hoặc 2x + 4 = 0
\(\Leftrightarrow\) 2x = 6 \(\Leftrightarrow\) 2x = -4
\(\Leftrightarrow\) x = \(\dfrac{6}{2}=3\) \(\Leftrightarrow\) x = \(\dfrac{-4}{2}=-2\)
Vậy x = 3 hoặc x = -2
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