bổ sung:
\(\left(2x-1\right)^2-25=0\Rightarrow\left(2x-1\right)^2=25\)
=> 2x - 1 = 5 => 2x = 5 + 1 = 6 => x = 6 : 2 = 3
=> 2x - 1 = -5 => 2x = -5 + 1 = -4 => x = -4 : 2 = -2
Tìm x
2x3-50x=0
2x(3x-5)-(5-3x)=0
9(3x-2)=x(2-3x)
(2x-1)2-25=0
25x2-2=0
X2-25=6x-9
(2x-1)2-(2x+5)(2x-5)=18
Tìm x biết 2(x+3)-x^2-3x=0
x^3+27+(x+3)(x-9)=0
4x^2-25-(2x-5)(2x+7)=0
8x^3-50x=0
(2x-1)^2-25=0
a) (2x - 1)2 - (2x + 5)(2x + 1) = 10
b) 92 (x - 1) + 25 .(1 - x) = 0
c) x2 + 3x - 4 = 0
( 2x – 1 )2 – 25 = 0
(2x-1)^2-25=0
Tìm x, biết:
a) 3x(x - 1) + x - 1 = 0;
b) (x - 2)( x 2 + 2x + 7) + 2( x 2 - 4) - 5(x - 2) = 0;
c) ( 2 x - 1 ) 2 - 25 = 0;
d) x 3 + 27 + (x + 3)(x - 9) = 0.
a) (2x - 1)2 - (2x + 5)(2x + 1) = 10
b) 92 (x - 1) + 25 .(1 - x) = 0
c) x2 + 3x - 4 = 0
Tìm x, biết
a,(2x-1)2 -25 = 0
b,8x3 -50x = 0
Tìm x:
a)9x^2-30x+25=0
b)25x^2-5x+1/4=0
c)9x^2-25=0
d)(2x-1)^2-(3x+2)^2=0
