Các câu hỏi tương tự
2x - 1/2 -1/6 -1/12-....-1/49.50 = 7 - 1/50 + x. Tìm x
Tìm x, biết:
\(2x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-...-\frac{1}{49.50}=7+\frac{1}{50}+x\)
2x - \(\frac{1}{2}\)- \(\frac{1}{6}\)- \(\frac{1}{12}\).......... - \(\frac{1}{49.50}\)= 7 - \(\frac{1}{50}\)+ x
Giúp mik vs mình cảm ơn !!!! (^-^)
1. Cho A = 1/(1.2)+1/(3.4)+...+1/(99.100).
Chứng minh 7/12 < A <5/6
2.Chứng minh:
1/(1.2)+1/(3.4)+...+1/(49.50)=1/26+1/27+...+1/50
a) A = 1/1.2+ 1/3.4+ 1/5.6+...+ 1/99.100
CMR: 7/12<A< 5/6
b) CMR: 1/1.2+ 1/3.4+ 1/5.6+...+1/49.50 = 1/26+ 1/27+ 1/28+...+1/50
1.Tìm x , biết
.2x -1/2-1/6-1/12-...- 1/49*50=7-1/50+x
2.Tìm các số nguyên x,y biết rằng
a.3/x+1/3=y/3
b.x/6-1/y=1/2
c.2/3x+y/6=1/2
1.Tính A=1/4+1/12+1/24....+1/20200
B=1/2+5/6+11/12+....+9899/9900
2.CMR:1/1.2+1/3.4+1/5.6+.....+1/49.50=1/26+1/27+...+1/50
Tìm x:
\(2x-3=x+\frac{1}{2}\)
\(4x-\left(2x+1\right)=3-\frac{1}{3}+x\)
\(2x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-...-\frac{1}{49\cdot50}=7-\frac{1}{50}+x\)
1, CMR: \(\frac{7}{12}<\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{97.98}+\frac{1}{99.100}<\frac{5}{6}\)
2, CMR: \(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{47.48}+\frac{1}{49.50}=\frac{1}{26}+\frac{1}{27}+\frac{1}{28}+...+\frac{1}{49}+\frac{1}{50}\)