Question

\(2\times|x-\frac{2}{3}|-\frac{1}{5}\)= 0

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dề bài tìm x

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Answer 1

\(2\times\left|x-\frac{2}{3}\right|-\frac{1}{5}=0.\)

\(2\times\left|x-\frac{2}{3}\right|=\frac{1}{5}\)

\(\left|x-\frac{2}{3}\right|=\frac{1}{5}\): \(2\)

\(\left|x-\frac{2}{3}\right|=\frac{1}{10}\)

\(\Rightarrow\)\(x-\frac{2}{3}=\frac{1}{10}\)hoặc \(-\frac{1}{10}\)

\(\Rightarrow\)\(x=\frac{1}{10}+\frac{2}{3}\)hoặc \(-\frac{1}{10}+\frac{2}{3}\)

\(\Rightarrow\)\(x=\frac{23}{30}\)hoặc \(\frac{17}{30}\)

Vậy \(x\in\){ \(\frac{23}{30}\); \(\frac{17}{30}\)}

Answer 2

\(2\left|x-\frac{2}{3}\right|-\frac{1}{5}=0\)

\(\Leftrightarrow2\left|x-\frac{2}{3}\right|=\frac{1}{5}\)

\(\Leftrightarrow\left|x-\frac{2}{3}\right|=\frac{1}{10}\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{2}{3}=\frac{1}{10}\\x-\frac{2}{3}=-\frac{1}{10}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{23}{30}\\x=\frac{17}{30}\end{cases}}\)

Vậy ....