\(\Rightarrow2+\frac{3}{\frac{7-4y}{2-y}}=7\)
\(\Rightarrow\frac{3}{\frac{7-4y}{2-y}}=5\)
\(\Rightarrow3\times\frac{2-y}{7-4y}=5\)
\(\Rightarrow\frac{2-y}{7-4y}=\frac{5}{3}\Rightarrow3\left(2-y\right)=5\left(7-4y\right)\)
\(\Rightarrow6-3y=35-20y\)
\(\Rightarrow17y=29\Rightarrow y=\frac{29}{17}\)