=8 k mk nha
mk đag âm 21 điểm
hết âm vào phần
câu hỏi của mk trả lời
rồi mk k cho
=\(\frac{5}{2}:\frac{1}{8}\)
=\(\frac{5}{2}\cdot8\)
=\(\frac{5\cdot2\cdot4}{2}\)
=\(20\)
nhớ nha
=8 k mk nha
mk đag âm 21 điểm
hết âm vào phần
câu hỏi của mk trả lời
rồi mk k cho
=\(\frac{5}{2}:\frac{1}{8}\)
=\(\frac{5}{2}\cdot8\)
=\(\frac{5\cdot2\cdot4}{2}\)
=\(20\)
nhớ nha
\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\right).x=\frac{1}{9}+\frac{2}{8}+\frac{3}{7} +...+\frac{8}{2}+\frac{9}{1}\)
chứng minh rằng:\(1+\frac{1}{2}+\frac{1}{2}+\frac{1}{12}+\left(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}\right)+...+\frac{1}{257}+\frac{1}{258}+....+\frac{1}{455}>1+\frac{1}{2}+\frac{1}{2}+\left(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}\right)+.....+\left(\frac{1}{257}+\frac{1}{258}+...+\frac{1}{512}\right)\)
\(a.\frac{-4}{11}.\frac{2}{5}+\frac{6}{11}.\frac{\left(-3\right)}{10}\)
\(b.\left|\left(\frac{2}{3}-1\frac{1}{2}\right)\right|:\frac{4}{3}+\frac{1}{2}\)
\(c.\frac{1}{8}.15\frac{2}{5}+1\frac{4}{5}.\frac{1}{8}-17\frac{1}{5}.\frac{1}{8}\)
\(d.\frac{1}{7}-\frac{8}{7}:8-3:\frac{3}{4}.\left(-2^{ }\right)^2\)
Giúp mình nha . Cảm ơn các bạn !
\((\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}).x=\frac{1}{9}+\frac{2}{8}+\frac{3}{7}+...+\frac{8}{2}+\frac{9}{1}\)
Ai bt làm thì giúp mk với!
Tính
a) \(\frac{1}{5}+\frac{-1}{6}+\frac{1}{7}+\frac{1}{-8}+\frac{1}{9}+\frac{1}{8}+\frac{1}{-7}+\frac{-1}{6}+\frac{-1}{5}\)
b) (-11).36-64.11
c) \(\frac{\frac{1}{3}+\frac{1}{7}+\frac{1}{13}}{\frac{2}{3}+\frac{2}{7}+\frac{2}{13}}.\frac{\frac{3}{4}+\frac{3}{16}+\frac{3}{64}+\frac{3}{256}}{1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}}+\frac{3}{8}\)
BÀI 1:
a/ \(\frac{2}{7}+\frac{-3}{8}+\frac{11}{7}+\frac{1}{3}+\frac{1}{7}+\frac{5}{-8}\)
b/ \(\frac{-3}{8}+\frac{12}{25}+\frac{5}{-8}+\frac{2}{-5}+\frac{13}{25}\)
c/ \(\frac{7}{8}+\frac{1}{8}.\frac{3}{8}+\frac{1}{8}.\frac{5}{8}\)
d/ \(\frac{-5}{6}.\frac{4}{19}+\frac{-7}{12}.\frac{4}{19}-\frac{40}{57}\)
e/ \(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}-\frac{1}{7}\)
f/ \(\left(\frac{2}{3}-\frac{1}{ }_{_4+\frac{5}{11}}\right):\left(\frac{5}{12}+1-\frac{7}{11}\right)\)
g/ \(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)
h/ \(1\frac{5}{18}-\frac{5}{18}:\left(\frac{1}{15}+1\frac{1}{12}\right)\)
i/ \(\frac{-1}{7}.\left(9\frac{1}{2}-8,75\right):\frac{2}{7}+62,5\%:1\frac{2}{3}\)
Tìm x, biết:
a)\(\frac{x+1}{2}=\frac{8}{x+1}\)
b)\(x:\left(9\frac{1}{2}-\frac{3}{2}\right)=\frac{0,4+\frac{2}{9}-\frac{2}{11}}{1,6+\frac{8}{9}-\frac{8}{11}}\)
Tính:
a) \(A=\frac{\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{7}}{\frac{8}{2}+\frac{8}{3}+\frac{8}{7}}}{\frac{\frac{1}{7}+\frac{1}{8}+\frac{1}{92}}{\frac{4}{7}+\frac{4}{8}+\frac{4}{92}}}\) ;b) \(B=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+.........+\frac{1}{120}\)
Giúp mình vs mình tick cho.
\(1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)