\(2.a=3.b=>\) \(a\)=\(\frac{3}{2}.b\)
\(5.b=7.c=>c=\frac{5}{7}.b\)
\(3.a+5.c=7.b+30\)
<=> \(3.\frac{3}{2}.b+5.\frac{5}{7}.b=7.b+30\)
<=>\(\frac{9}{2}.b+\frac{25}{7}.b=7.b+30\)
<=>\(\frac{113}{14}.b=7.b+30\)
<=>\(\frac{15}{14}.b=30\)
<=>\(b=28\)
suy ra: \(a=\frac{3}{2}.28=42\)
\(c=\frac{5}{7}.28=20\)
vậy \(a=42;b=28;c=20\)