=> \(5^{x-1}\)= 27 - 2
=> \(5^{x-1}\)= 25
=> x - 1 = 2
=> x = 2 + 1 = 3
Ta có: 27 - 5x - 1 = 2.
=> 5x - 1 = 25.
5x - 1 = 52.
=> x - 1 = 2
x = 3.
1/ 3(x - 1) - 5(x - 2) = 4(x + 1)
2/ -2(x - 2) - 4(x + 1) = -3(x + 3)
3/ 3x\(^2\) + 2x = 0
4/ x\(^2\) - 5x = 0
5/ (2x - 3)\(^2\) = 36
6/ (5x - 1)\(^3\) = 125
7/ 3\(^x\) + 1 = 27
Tìm x
a) -x/27 -1 = 2/3
b) x - 4 = -14/35 : 20/-21
c) x + 2/3 = -1/12 . -4/5
d) 1/5 - 3/5x = -15/14 :20/-21
e) -3/7x = 3/5 . 28/9
f)1/2x + 3/5x = -2/3
a) x+x+x + 91 = -2
b) -125 - (3x+1) = -2 . -27
c) /5x +1/ =14
a,so sánh 920 và 2713
b,1,(5x-1) . 3-2=70
2, |2x-1|=5
5x - 2 .(x-1)=-4.3.125.(-25).8
7x + 6 .(3-x)=27 - 20 + 73
6x - 5 . ( x- 7 ) = ( 27 - 514 ) - ( 486 - 73 )
3./x+4/-2.(x-1)= 7-2x
2./x-6/+7x-2=/x-6/+ 7x
//=giá trị tuyệt đối
5x-7=3x-15
Xmu2=16
(2x-1)mu3=-27
Tìm số tự nhiên x, biết
a) 2 x : 2 = 8
b) 3 x : 3 2 = 243
c) 625 : 5 x = 52
d) 3 x : 27 = 9
e) 7 x + 1 : 7 = 49
f) 112 x + 1 : 11 = 121
Tìm số tự nhiên x, biết
a, 2 x : 2 = 8
b, 3 x : 3 2 = 243
c, 625 : 5 x = 5 2
d, 3 x : 27 = 9
e, 7 x + 1 : 7 = 49
f, 11 2 x + 1 : 11 = 121
Tìm tổng số nguyên x bt
a)—152—(3x+1)=(—2).(—27)
b) |5x+1|= 11
c) 8x.(5—x)=0
a) (3x-6)^3=27
b) (125:5x)^2=25
c) (12*194+6*4372+3*69*4):[(1+5+9+.....+61)+[65*2-26]
